document.write( "Question 700737: The widith of a rectangle is 3 cm less than the length. The area of a rectangle is 54cm^2. Find the widith and length. \n" ); document.write( "
Algebra.Com's Answer #432238 by Simnepi(216)![]() ![]() You can put this solution on YOUR website! To solve problems like these you have to make an equation from the information given. \n" ); document.write( "Let's call the length x. \n" ); document.write( "Because the width is 3 less than the length, we can say that.... \n" ); document.write( "the width is (x-3). \n" ); document.write( "We know that area = length x width. So now we can write \n" ); document.write( "54 = x*(x-3). \n" ); document.write( "Multiplying out the brackets gives \n" ); document.write( "54 = \n" ); document.write( "rearranging this gives \n" ); document.write( " \n" ); document.write( "So we have a quadratic equation which will have 2 solutions. \n" ); document.write( "To find what they are we have to find factors of -54. These are plus/minus 1 and 54, plus/minus 2 and 27, plus/minus 3 and 18, plus/minus 6 and 9. \n" ); document.write( "Because there is -3x in the quadratic equation we are looking for factors which we can add or take to make to make -3. \n" ); document.write( "Obviously, the factors we must choose are +6 and -9, these will multiply to make -54 and we can add them to make -3. \n" ); document.write( "We will use those factors to factorise the equation \n" ); document.write( "Thus we get \n" ); document.write( "(x+6)(x-9) = 0 \n" ); document.write( "because one of these factors must equal 0 we can say that either \n" ); document.write( "(x+6) = 0 OR (x-9) = 0 \n" ); document.write( "solving these linear equations gives \n" ); document.write( "x = -6, OR x = 9 \n" ); document.write( "The first solution is nonsense as you can't have a negative measurement \n" ); document.write( "so the length of the rectangle is 9 cm. \n" ); document.write( "Hope that helps. \n" ); document.write( " |