document.write( "Question 701141: Can you please help me solve this equation of linear functions using substitution?\r
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document.write( "3x + 4y = 6
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document.write( "3x - 4y = 30\r
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document.write( "Thank you. \n" );
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Algebra.Com's Answer #432237 by star68(2)![]() ![]() ![]() You can put this solution on YOUR website! 3x + 4y = 6 ...equation 1 \n" ); document.write( "3x - 4y = 30 ...equation 2 \n" ); document.write( " Subtitute eq1+eq2 \n" ); document.write( "3x+3x = 6+30 \n" ); document.write( "6x=36 \n" ); document.write( "x=36/6 \n" ); document.write( "x=6 \n" ); document.write( " Substitute x=6 into equation 2 \n" ); document.write( "3(6)-4y = 30 \n" ); document.write( "18-4y=30 \n" ); document.write( "-4y=30-18 \n" ); document.write( "-4y=12 \n" ); document.write( "y= 12/-4 \n" ); document.write( "y= -3 \n" ); document.write( " Therefore, x=3 and y=-3 \n" ); document.write( " |