document.write( "Question 701141: Can you please help me solve this equation of linear functions using substitution?\r
\n" ); document.write( "\n" ); document.write( "3x + 4y = 6
\n" ); document.write( "3x - 4y = 30\r
\n" ); document.write( "\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #432237 by star68(2)\"\" \"About 
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3x + 4y = 6 ...equation 1
\n" ); document.write( "3x - 4y = 30 ...equation 2
\n" ); document.write( " Subtitute eq1+eq2
\n" ); document.write( "3x+3x = 6+30
\n" ); document.write( "6x=36
\n" ); document.write( "x=36/6
\n" ); document.write( "x=6
\n" ); document.write( " Substitute x=6 into equation 2
\n" ); document.write( "3(6)-4y = 30
\n" ); document.write( "18-4y=30
\n" ); document.write( "-4y=30-18
\n" ); document.write( "-4y=12
\n" ); document.write( "y= 12/-4
\n" ); document.write( "y= -3
\n" ); document.write( " Therefore, x=3 and y=-3
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