document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701052>Question 701052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this linear equation. I am supposed to use substitution and I can't figure it out.\r<BR>\n" );
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document.write( "x + y = 45<BR>\n" );
document.write( "0.8x + 0.6y = 31 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432195 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=-x+45<BR>\n" );
document.write( "0.8x+0.6(-x+45)=31<BR>\n" );
document.write( "0.8x-0.6x+27=31<BR>\n" );
document.write( "0.2x=31-27<BR>\n" );
document.write( "0.2x=4<BR>\n" );
document.write( "x=4/0.2<BR>\n" );
document.write( "x=20<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "0.8*20+0.6y=31<BR>\n" );
document.write( "16+0.6y=31<BR>\n" );
document.write( "0.6y=31-16<BR>\n" );
document.write( "0.6y=15<BR>\n" );
document.write( "y=15/0.6<BR>\n" );
document.write( "y=25<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "20+25=45 </SPAN>\n" );
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