document.write( "Question 701065: The angle a kite string makes with the ground is 24º. If 80 m of string has been let out, how high is the kite above the ground?\r
\n" ); document.write( "\n" ); document.write( "The angles of elevation from a point A and a point B to the top of a mountain 780m high are shown. Point A is 67 degrees and point B is 48 degrees. How long would a tunnel be through the mountain, connecting A and B?
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Algebra.Com's Answer #432187 by mananth(16946)\"\" \"About 
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The kite is vertically above the ground. height ?
\n" ); document.write( "The length of sting = hypotenuse= 80m
\n" ); document.write( "The angle of elevation = 24 deg.\r
\n" ); document.write( "\n" ); document.write( "Sin theta = opposite side/ hypotenuse\r
\n" ); document.write( "\n" ); document.write( "sin 24 = opposite side/80\r
\n" ); document.write( "\n" ); document.write( "height of kite = 80 * sin 24\r
\n" ); document.write( "\n" ); document.write( "use calc to find the height\r
\n" ); document.write( "\n" ); document.write( ".....\r
\n" ); document.write( "\n" ); document.write( "Point A elevation is 67 deg
\n" ); document.write( "point B elevation = 48 deg.\r
\n" ); document.write( "\n" ); document.write( "height of mountain = 780 m\r
\n" ); document.write( "\n" ); document.write( "A to mountain foot distance = 780/Tan 67 .............. (1)
\n" ); document.write( "B to mountain foot distance = 780/tan 48 ..................(2)\r
\n" ); document.write( "\n" ); document.write( "distance AB = (2)-(1)\r
\n" ); document.write( "\n" ); document.write( "780/1.11 -780/2.35 \r
\n" ); document.write( "\n" ); document.write( "about 370.8 m is the length of the tunnel.
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