document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701047>Question 701047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the area under a curve with the equation y= negative 2x to the 2nd power + 6x + 36 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432179 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the area under a curve with the equation y= negative 2x to the 2nd power + 6x + 36<BR>\n" );
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document.write( "y = -2x^2 + 6x + 36<BR>\n" );
document.write( "Assuming you mean bounded by the x-axis:<BR>\n" );
document.write( "It intersects the x-axis at x = -3 and x = +6<BR>\n" );
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document.write( "INT(x) = -2x^3/3 + 3x^2 + 36x  (Ignore the constant of integration)<BR>\n" );
document.write( "INT(6) = -144 + 108 + 216 = 180<BR>\n" );
document.write( "INT(-3) = 18 + 27 - 108 = -63<BR>\n" );
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document.write( "INT(6) - INT(-3) = 243 sq units<BR>\n" );
document.write( "Area = 243 sq units<BR>\n" );
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