document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62472>Question 62472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> determine the equation of the line passing through the points (4,-3) and (-4,6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43216 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST WE FIND THE SLOPE BY (Y2-Y1)/(X2-X1)<BR>\n" );
document.write( "(6+3)/(-4-4)<BR>\n" );
document.write( "9/-8=-9/8 NOW SUBSTITUTING ANY SET OF X&Y VALUES INTO THE LINE EQUATION<BR>\n" );
document.write( "Y=mX+b WE FIND THE Y INTERCEPT VALUE (b)<BR>\n" );
document.write( "-3=-9/8*4+b<BR>\n" );
document.write( "-3=-36/8+b<BR>\n" );
document.write( "-3=-4.5+b<BR>\n" );
document.write( "b=-3+4.5<BR>\n" );
document.write( "b=1.5 THUS THE LINE EQUATION IS<BR>\n" );
document.write( "Y=-9/8X+1.5 <BR>\n" );
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