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document.write( "The sum of three consecutive odd integers is 41 more than twice the smallest.Find the three integers \n" );
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Algebra.Com's Answer #432153 by checkley79(3341) ![]() You can put this solution on YOUR website! LET X, X+2 & X+4 BE THE 3 ODD NUMBERS. \n" ); document.write( "X+X+2+X+4=41+2X \n" ); document.write( "3X+6=41+2X \n" ); document.write( "3X-2X=41-6 \n" ); document.write( "X=35 ANS. FOR THE FIST INTEGER. \n" ); document.write( "35+2=37 ANS. FOR THE MIDDLE INTEGER. \n" ); document.write( "35+4=39 ANS. FOR THE LAST INTEGER. \n" ); document.write( "PROOF: \n" ); document.write( "35+37+39=41+2*35 \n" ); document.write( "111=41+70 \n" ); document.write( "111=111 \n" ); document.write( " |