document.write( "Question 700945: The Compound interest is 1590 for 2 years at the rate of 12% PA Find the simple interest for the same period for 16% \r
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document.write( "Hint Answer is 2000
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document.write( "Compound interest=1590 it is not the principal
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document.write( "Rate =12%
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document.write( "Time=2years \n" );
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Algebra.Com's Answer #432088 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The Compound interest is 1590 for 2 years at the rate of 12% PA Find the simple interest for the same period for 16% \n" ); document.write( "Hint Answer is 2000 \n" ); document.write( "Compound interest=1590 it is not the principal \n" ); document.write( "Rate =12% \n" ); document.write( "Time=2years \n" ); document.write( "---------- \n" ); document.write( "Compound information: \n" ); document.write( "P+I = P(1+(r/n))^(nt) \n" ); document.write( "P+1590 = P(1+(0.12/1))^(1*2) \n" ); document.write( "P+1590 = P(1.2544) \n" ); document.write( "0.2544P = 1590 \n" ); document.write( "P = $6250 \n" ); document.write( "----- \n" ); document.write( "Simple Interest information: \n" ); document.write( "I = Prt \n" ); document.write( "I = 6250*0.16*2 \n" ); document.write( "--- \n" ); document.write( "I = $2000 \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |