document.write( "Question 700895:
\n" ); document.write( "two consecutive odd integers are such, that one-third the smaller one is greater than one seventh of the larger one by 6. find the number
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Algebra.Com's Answer #432071 by checkley79(3341)\"\" \"About 
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LET X & X+2 BE THE 2 ODD INTEGERS.
\n" ); document.write( "(X/3)=[(X+2)/7]+6
\n" ); document.write( "X/3=(X+2+6*7)/7
\n" ); document.write( "X/3=(X+2+42)/7
\n" ); document.write( "X/3=(X+44)/7 CROSS MULTIPLY.
\n" ); document.write( "7X=3(X+44)
\n" ); document.write( "7X=3X+132
\n" ); document.write( "7X-3X=132
\n" ); document.write( "4X=132
\n" ); document.write( "X=132/4
\n" ); document.write( "X=33 ANS. FOR THE SMALLER ODD INTEGER.
\n" ); document.write( "33+2=35 ANS. FOR THE LARGER ODD INTEGER.
\n" ); document.write( "PROOF:
\n" ); document.write( "33/3=(35/7)+6
\n" ); document.write( "11=5+6
\n" ); document.write( "11=11
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