document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=700800>Question 700800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 0.5(6x-4)=4x-9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #432001 by </B><A HREF=/tutors/aboutme.mpl?userid=jpvn2015><B>jpvn2015(54)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jpvn2015><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=432001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply the .5 by the 6x and add it to the product of .5 and -4. Thus, the problem will look like this: 3x - 2 = 4x - 9.\r<BR>\n" );
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document.write( "Add \"2\" to both sides of the equation: 3x = 4x - 7.\r<BR>\n" );
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document.write( "Subtract 4x from both sides of the equation: -x = -7 or simply, x = 7.  \r<BR>\n" );
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document.write( "Thus, x is equal to seven. </SPAN>\n" );
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