document.write( "Question 700426: a number of two digits is 9 more than 5 times the sum of its digits. its ten's digit is one more that its unit's digit. find the number. \n" ); document.write( "

Algebra.Com's Answer #431968 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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let a = the 10's digit
\n" ); document.write( "let b = the units
\n" ); document.write( "Then
\n" ); document.write( "10a+b = the two digit number
\n" ); document.write( ":
\n" ); document.write( "a number of two digits is 9 more than 5 times the sum of its digits.
\n" ); document.write( "10a + b = 5(a + b) + 9
\n" ); document.write( "10a + b = 5a + 5b + 9
\n" ); document.write( "10a - 5a = 5b - b + 9
\n" ); document.write( "5a = 4b + 9
\n" ); document.write( ":
\n" ); document.write( "its ten's digit is one more that its unit's digit.
\n" ); document.write( "a = b + 1
\n" ); document.write( ":
\n" ); document.write( "Replace a with (b+1) in the the eq: 5a = 4b + 9
\n" ); document.write( "5(b+1) = 4b + 9
\n" ); document.write( "5b + 5 = 4b + 9
\n" ); document.write( "5b - 4b = 9 - 5
\n" ); document.write( "b = 4
\n" ); document.write( ":
\n" ); document.write( "I'll let you find a, check the obtained number in the 1st statement so see if it is true\r
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\n" ); document.write( "\n" ); document.write( " find the number. \n" ); document.write( "

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