document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=700731>Question 700731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of a:<BR>\n" );
document.write( "The line through (-2,a) and (a,3) has slope -1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #431962 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=431962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of a:<BR>\n" );
document.write( "The line through (-2,a) and (a,3) has slope -1/2<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Standard form of equation for a line: y=mx+b, m=slope, b=y-intercept<BR>\n" );
document.write( "slope=&#8710;y/&#8710;x<BR>\n" );
document.write( "=(3-a)/(a-(-2))<BR>\n" );
document.write( "=(3-a)/(a+2)=-1/2<BR>\n" );
document.write( "3-a=-a/2-1<BR>\n" );
document.write( "a/2=4<BR>\n" );
document.write( "a=8                                                                              </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );