document.write( "Question 62435: I need some help with log please\r
\n" ); document.write( "\n" ); document.write( "Solve ln(3+3x)-ln(x-4)=ln5 \r
\n" ); document.write( "\n" ); document.write( "thanks for your time \n" ); document.write( "

Algebra.Com's Answer #43195 by uma(370) $\"\"$ $\"About$

You can put this solution on YOUR website!
ln(3+3x) - ln(x-4) = ln5\r
\n" ); document.write( "\n" ); document.write( "==> ln[(3+3x)/(x-4)] = ln 5 [because lna - ln b = ln(a/b)]\r
\n" ); document.write( "\n" ); document.write( "Removing ln from either side we get....\r
\n" ); document.write( "\n" ); document.write( "[(3+3x)/(x-4)] = 5\r
\n" ); document.write( "\n" ); document.write( "Multiplying by (x-4) on either side we get..\r
\n" ); document.write( "\n" ); document.write( "3 + 3x = 5(x-4)
\n" ); document.write( "==> 3 + 3x = 5x - 20\r
\n" ); document.write( "\n" ); document.write( "==> 3 + 3x - 5x = 5x - 20 - 5x\r
\n" ); document.write( "\n" ); document.write( "==> 3 - 2x = - 20\r
\n" ); document.write( "\n" ); document.write( "==> 3 - 2x - 3 = - 20 - 3
\n" ); document.write( "==> -2x = - 23\r
\n" ); document.write( "\n" ); document.write( "==> -2x/-2 = -23/-2\r
\n" ); document.write( "\n" ); document.write( "==> x = 23/2\r
\n" ); document.write( "\n" ); document.write( "==> x = 11.5\r
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\n" ); document.write( "\n" ); document.write( "Good Luck!!!
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