document.write( "Question 700031: A fright train passes the Old Towne train station at 11:00 A.M. going 30 mph. Ten minutes later, a passenger train, headed in the same direction on an adjacent track, passes the same station at 45 mph. At what time will the passenger train catch the fright train?
\n" ); document.write( "My book gives an answer as 11:30 A.M., but I get another answer. Can you help, please? Thank you in advance. \n" ); document.write( "

Algebra.Com's Answer #431808 by KMST(5328) $\"\"$ $\"About$

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$\"t\"$ = time in hours since 11:00 AM
\n" ); document.write( "10 minutes = $\"10%2F60=1%2F6\"$ hours
\n" ); document.write( "The distance from Old Towne station after $\"t\"$ is
\n" ); document.write( " $\"30t\"$ for the freight train, and
\n" ); document.write( " $\"45%28t-1%2F6%29=45t-45%2F6=45t-7.5\"$ for the passenger train.
\n" ); document.write( "When the passenger train catches up to the freight train,
\n" ); document.write( " $\"45t-7.5=30t\"$ --> $\"45t-7.5-30t=30t-30y\"$ --> $\"15t-7.5=0\"$ --> $\"15t-7.5%2B7.5=0%2B7.5\"$ --> $\"15t=7.5\"$ --> $\"15t%2F15=7.5%2F15\"$ --> $\"highlight%28t=0.5%29\"$
\n" ); document.write( "The passenger train catches up to the freight train 0.5 hours (half an hour, or 30 minutes) after 11:00 AM, at 11:30 AM. \n" ); document.write( "

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