document.write( "Question 700301: The measures of two supplementary angles are 6y + 3 and 4y - 13.Find the measures of the angles. \n" ); document.write( "

Algebra.Com's Answer #431778 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "two supplementary angles $\"alpha\"$ and $\"beta\"$ add up to $\"180\"$ °\r
\n" ); document.write( "\n" ); document.write( "so, $\"alpha%2Bbeta=180\"$ °\r
\n" ); document.write( "\n" ); document.write( "if $\"alpha=6y+%2B+3\"$ and $\"beta=4y+-13\"$ , than we have\r
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\n" ); document.write( "\n" ); document.write( " $\"6y+%2B+3%2B4y+-13=180\"$ °...solve for $\"y\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"10y+-10=180\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"10y+=180%2B10\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"10y+=190\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"y+=190%2F10\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"y+=19\"$ °......now find $\"alpha\"$ and $\"beta\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"alpha=6y+%2B+3\"$ ° ...plug in $\"y\"$ value\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=6%2A19+%2B+3\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=114+%2B+3\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28alpha=117%29\"$ °\r
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\n" ); document.write( "\n" ); document.write( "and $\"beta=4%2A19+-13\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"beta=76+-13\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28beta=63%29\"$ °\r
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