document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=700301>Question 700301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measures of two supplementary angles are 6y + 3 and 4y - 13.Find the measures of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #431774 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=431774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6y+3+4y-13=180<BR>\n" );
document.write( "10y=180+10<BR>\n" );
document.write( "10y=190<BR>\n" );
document.write( "y=190/10<BR>\n" );
document.write( "y=19<BR>\n" );
document.write( "6y+3=117<BR>\n" );
document.write( "4y-13=63 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );