document.write( "Question 700161: I am working on mixed numbers and variables in fractions. The problem is Solve for x: (2 1/2)/24)=x/30
\n" ); document.write( "I'm not quite sure how to start. Do I multiply both sides by 24 to leave the mixed number by its self which would give me 2 1/2 = 3x/5 then multiply the both sides by 5 to get 25/2 = 3x then divide by 3 to get 25/6. Or do I change the mixed number to a decimal so it is 2.5/24 = x/30. I'm just really confused...
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Algebra.Com's Answer #431698 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Either process results in the same answer -- given CORRECT arithmetic. In your first method you also need to convert your mixed number to an improper fraction.\r
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\n" ); document.write( "\n" ); document.write( "Multiply by the LHS denominator. (Note: 6 goes into 24 four times and into 30 five times)\r
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\n" ); document.write( "\n" ); document.write( "Now convert to an improper fraction. 2 is four halves plus one-half is \r
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\n" ); document.write( "\n" ); document.write( "Multiply by the reciprocal of the coefficient on \r
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\n" ); document.write( "\n" ); document.write( "Then you can integer divide 25 by 8 to convert back to a mixed number if that happens to tickle your fancy.\r
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\n" ); document.write( "\n" ); document.write( "If you do it by changing everything to decimals, you end up with which is the same thing as 3 and 1/8 or 25/8.\r
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\n" ); document.write( "\n" ); document.write( "Now for the way I would have done it in the first place.\r
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\n" ); document.write( "\n" ); document.write( "Step 1: Multiply the LHS by 1 in the form \r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by 48\r
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\n" ); document.write( "\n" ); document.write( "Reduce the fraction in the RHS\r
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\n" ); document.write( "\n" ); document.write( "Multiply by the reciprocal of the coefficient in the LHS\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
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\"The

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