document.write( "Question 700160: Two planes which are 3260 miles apart,fly toward each other. Their speeds differ by 55 mph.If they pass each other in 4 hours, what is the speed of each? \n" ); document.write( "

Algebra.Com's Answer #431667 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Think of one plane as being stationary and
\n" ); document.write( "the other plane approaching at the sum of their speeds.
\n" ); document.write( "Let $\"+s+\"$ = the speed of the slower plane
\n" ); document.write( " $\"+s+%2B+55+\"$ = the speed of the faster plane
\n" ); document.write( " $\"+3260+=+%28+s+%2B+s+%2B+55+%29%2A4+\"$
\n" ); document.write( " $\"+3260+=+%28+2s+%2B+55+%29%2A4+\"$
\n" ); document.write( " $\"+3260+=+8s+%2B+220+\"$
\n" ); document.write( " $\"+8s+=+3040+\"$
\n" ); document.write( " $\"+s+=+380+\"$
\n" ); document.write( " $\"+s+%2B+55+=+435+\"$
\n" ); document.write( "Their speeds are 380 mi/hr and 435 mi/hr
\n" ); document.write( "check:
\n" ); document.write( " $\"+380%2A4+=+1520+\"$ mi
\n" ); document.write( " $\"+435%2A4+=+1740+\"$ mi
\n" ); document.write( " $\"+1520+%2B+1740+=+3260+\"$ mi
\n" ); document.write( "OK
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