document.write( "Question 700101: Write the equation of a circle that passes through the points A(4;0) , B(0;2) and whose center belongs to the line of equation y+2x=0 \n" ); document.write( "
Algebra.Com's Answer #431631 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Write the equation of a circle that passes through the points A(4;0) , B(0;2) and whose center belongs to the line of equation y+2x=0 \n" ); document.write( "----------------- \n" ); document.write( "Find the center. The center is equidistant from the 2 points and on the line. \n" ); document.write( "--> The center will be on the line that's the perpendicular bisector of the line joining the 2 points. \n" ); document.write( "The slope of lines thru the 2 points = -1/2 --> perpendicular lines have a slope of +2. \n" ); document.write( "The midpoint of A & B is (2,1) \n" ); document.write( "Using y = mx+b and (2,1) --> y = 2x - 3 is the perp. bisecting line. \n" ); document.write( "-------------- \n" ); document.write( "The center is the intersection of y = 2x-3 and y+2x = 0 \n" ); document.write( "--> (3/4,-3/2) \n" ); document.write( "------------ \n" ); document.write( "The radius is the distance from the center to either A or B \n" ); document.write( " \n" ); document.write( "-------- \n" ); document.write( "the circle is \n" ); document.write( "================ \n" ); document.write( "PS Use commas for points, eg, (4,0) and (0,2) \n" ); document.write( " \n" ); document.write( " |