document.write( "Question 700101: Write the equation of a circle that passes through the points A(4;0) , B(0;2) and whose center belongs to the line of equation y+2x=0 \n" ); document.write( "
Algebra.Com's Answer #431631 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Write the equation of a circle that passes through the points A(4;0) , B(0;2) and whose center belongs to the line of equation y+2x=0
\n" ); document.write( "-----------------
\n" ); document.write( "Find the center. The center is equidistant from the 2 points and on the line.
\n" ); document.write( "--> The center will be on the line that's the perpendicular bisector of the line joining the 2 points.
\n" ); document.write( "The slope of lines thru the 2 points = -1/2 --> perpendicular lines have a slope of +2.
\n" ); document.write( "The midpoint of A & B is (2,1)
\n" ); document.write( "Using y = mx+b and (2,1) --> y = 2x - 3 is the perp. bisecting line.
\n" ); document.write( "--------------
\n" ); document.write( "The center is the intersection of y = 2x-3 and y+2x = 0
\n" ); document.write( "--> (3/4,-3/2)
\n" ); document.write( "------------
\n" ); document.write( "The radius is the distance from the center to either A or B
\n" ); document.write( "\"r%5E2+=+3.25%5E2+%2B+1.5%5E2+=+12.8125\"
\n" ); document.write( "--------
\n" ); document.write( "the circle is \"%28x+-+3%2F4%29%5E2+%2B+%28y+%2B+3%2F2%29%5E2+=+12.8125\"
\n" ); document.write( "================
\n" ); document.write( "PS Use commas for points, eg, (4,0) and (0,2)
\n" ); document.write( "
\n" ); document.write( "
\n" );