document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62413>Question 62413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2x - 3y = 0 and 3x + 2y = 13, find x + y.  Do I solve for x and y and then just add them.  Please show me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43162 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes your idea is correct.\r<BR>\n" );
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document.write( "Equation 1 : 2x - 3y = 0 <BR>\n" );
document.write( "Equation 2 : 3x + 2y = 13\r<BR>\n" );
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document.write( "Multiply the first equation by 2 and the second equation by 3. This will give a -6y in the first equation and a 6y in the second equation which can easily be eliminated.\r<BR>\n" );
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document.write( "New Equation 1 : 4x - 6y = 0 <BR>\n" );
document.write( "New Equation 2 : 9x + 6y = 39\r<BR>\n" );
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document.write( "Add the two equations together to get<BR>\n" );
document.write( "13x = 39\r<BR>\n" );
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document.write( "Obviously x must be 3. Substitute x=3 into one of the two equations.<BR>\n" );
document.write( "2*3 - 3y = 0 <BR>\n" );
document.write( "6=3y ie y must be 2<BR>\n" );
document.write( "Therefore x + y = 3 + 2 = 5 </SPAN>\n" );
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