document.write( "Question 62331: sqrt(3x-5) - sqrt(x+7)=2 solve for x...may be more than one answer \n" ); document.write( "
Algebra.Com's Answer #43161 by jai_kos(139)![]() ![]() ![]() You can put this solution on YOUR website! Given sqrt(3x-5) - sqrt(x+7)= 2\r \n" ); document.write( "\n" ); document.write( "==> sqrt(3x -5) = 2 + sqrt( x+7)\r \n" ); document.write( "\n" ); document.write( "Square on both sides, we get\r \n" ); document.write( "\n" ); document.write( "( 3x -5) = [ 2 + sqrt(x + 7)] ^2 \n" ); document.write( " \n" ); document.write( "3x - 5 = 4 + ( x + 7) + 4sqrt( x + 7)\r \n" ); document.write( "\n" ); document.write( "3x - 5 - 4 -x - 7 = 4sqrt ( x + 7)\r \n" ); document.write( "\n" ); document.write( "2x - 16 = 4 sqrt(x +7)\r \n" ); document.write( "\n" ); document.write( "Divide throughout by 2, we get\r \n" ); document.write( "\n" ); document.write( "x - 8 = 2sqrt (x + 7)\r \n" ); document.write( "\n" ); document.write( "Square on both sides, we get\r \n" ); document.write( "\n" ); document.write( "( x -8) ^ 2 = 4 ( x + 7)\r \n" ); document.write( "\n" ); document.write( "x ^2 - 16x + 64 = 4x + 28\r \n" ); document.write( "\n" ); document.write( "x ^2 - 16x -4x + 64 - 28 = 0\r \n" ); document.write( "\n" ); document.write( "x^2 - 20x + + 36 = 0\r \n" ); document.write( "\n" ); document.write( "x^2 - 18x - 2x + 36 = 0\r \n" ); document.write( "\n" ); document.write( "x (x - 18) - 2 (x - 18) = 0\r \n" ); document.write( "\n" ); document.write( "( x - 2) ( x- 18) = 0 \r \n" ); document.write( "\n" ); document.write( "==> x - 2 = 0 or x - 18 = 0\r \n" ); document.write( "\n" ); document.write( "==> x = 2 or x = 18\r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |