document.write( "Question 699846: I just wanted to see if I have this expression written correctly for the following question:\r
\n" ); document.write( "\n" ); document.write( "Thomas rowed upstream at 6 mph and downstream at 12 mph. If Thomas rowed for thre hours, how far was his entire trip, upstream and downstream?\r
\n" ); document.write( "\n" ); document.write( "I wrote the equation as: 6x + 12 (3-x). Is this correct?
\n" ); document.write( "

Algebra.Com's Answer #431569 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Thomas rowed upstream at 6 mph and downstream at 12 mph. If Thomas rowed for three hours, how far was his entire trip, upstream and downstream?
\n" ); document.write( ":
\n" ); document.write( "Let d = the distance up or down stream
\n" ); document.write( ":
\n" ); document.write( "write a time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "time up + time down = 3 hrs
\n" ); document.write( "\"d%2F6\" + \"d%2F12\" = 3
\n" ); document.write( "multiply by 12 to clear the denominators, find d, total dist = 2d
\n" ); document.write( "
\n" );