document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=699756>Question 699756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the reciprocal of a number and the reciprocal of 3 less than the  number is 8 times the reciprocal of the original number. find the original number. \r<BR>\n" );
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document.write( "choices (in case this helps)<BR>\n" );
document.write( "a) 7/2<BR>\n" );
document.write( "b) -2<BR>\n" );
document.write( "c) 8/5<BR>\n" );
document.write( "d) 21/8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #431548 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=431548\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let number be x<BR>\n" );
document.write( "reciprocal = 1/x\r<BR>\n" );
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document.write( "reciprocal of 3<BR>\n" );
document.write( "=1/3<BR>\n" );
document.write( "(1/3)-x\r<BR>\n" );
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document.write( "(1/x) + (1/(x-3) = (8/x)\r<BR>\n" );
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document.write( "multiply equation by x(x-3)\r<BR>\n" );
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document.write( "(x-3) +x=8(x-3)\r<BR>\n" );
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document.write( "x-3+x=8x-24\r<BR>\n" );
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document.write( "6x=21<BR>\n" );
document.write( "x=7/2\r<BR>\n" );
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document.write( " </SPAN>\n" );
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