document.write( "Question 699628: i need help to solve this by the substitution method please, can you please show me steps to how you solve this, thank you\r
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\n" ); document.write( "\n" ); document.write( "2x-y=5 9x-4y=23
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Algebra.Com's Answer #431455 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
2x - y = 5
\n" ); document.write( " 9x- 4y = 23
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\n" ); document.write( "Use the 1st equation for substitution
\n" ); document.write( "2x - y = 5
\n" ); document.write( "Subtract 2x from both sides
\n" ); document.write( "-y = -2x + 5
\n" ); document.write( "y has to be positive, multiply both sides by -1
\n" ); document.write( "y = 2x - 5
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\n" ); document.write( "In the 2nd equation,
\n" ); document.write( "9x - 4y = 23
\n" ); document.write( " substitute (2x-5) for y
\n" ); document.write( "9x - 4(2x-5) = 23
\n" ); document.write( "9x - 8x + 20 = 23
\n" ); document.write( "subtract 20 from both sides
\n" ); document.write( "x = 23 - 20
\n" ); document.write( "x = 3
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\n" ); document.write( "We know y = 2x -5
\n" ); document.write( "substitute x with 3
\n" ); document.write( "y = 2(3) - 5
\n" ); document.write( "y = 6 - 5
\n" ); document.write( "y = 1
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\n" ); document.write( "Our solution x=3, y=1 should be checked in both equations
\n" ); document.write( " 2x - y = 5
\n" ); document.write( "replace x and y
\n" ); document.write( "2(3) - 1 = 5
\n" ); document.write( "and
\n" ); document.write( "9x- 4y = 23
\n" ); document.write( "9(3) - 4(1) = 23
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\n" ); document.write( "HOw about this, enough steps for you to understand what happened here? C
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