document.write( "Question 699628: i need help to solve this by the substitution method please, can you please show me steps to how you solve this, thank you\r
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document.write( "2x-y=5 9x-4y=23 \n" );
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Algebra.Com's Answer #431455 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 2x - y = 5 \n" ); document.write( " 9x- 4y = 23 \n" ); document.write( ": \n" ); document.write( "Use the 1st equation for substitution \n" ); document.write( "2x - y = 5 \n" ); document.write( "Subtract 2x from both sides \n" ); document.write( "-y = -2x + 5 \n" ); document.write( "y has to be positive, multiply both sides by -1 \n" ); document.write( "y = 2x - 5 \n" ); document.write( ": \n" ); document.write( "In the 2nd equation, \n" ); document.write( "9x - 4y = 23 \n" ); document.write( " substitute (2x-5) for y \n" ); document.write( "9x - 4(2x-5) = 23 \n" ); document.write( "9x - 8x + 20 = 23 \n" ); document.write( "subtract 20 from both sides \n" ); document.write( "x = 23 - 20 \n" ); document.write( "x = 3 \n" ); document.write( ": \n" ); document.write( "We know y = 2x -5 \n" ); document.write( "substitute x with 3 \n" ); document.write( "y = 2(3) - 5 \n" ); document.write( "y = 6 - 5 \n" ); document.write( "y = 1 \n" ); document.write( ": \n" ); document.write( "Our solution x=3, y=1 should be checked in both equations \n" ); document.write( " 2x - y = 5 \n" ); document.write( "replace x and y \n" ); document.write( "2(3) - 1 = 5 \n" ); document.write( "and \n" ); document.write( "9x- 4y = 23 \n" ); document.write( "9(3) - 4(1) = 23 \n" ); document.write( ": \n" ); document.write( "HOw about this, enough steps for you to understand what happened here? C \n" ); document.write( " \n" ); document.write( " |