document.write( "Question 699533: \"%28%28x-1%29%2F%28x%5E2-5x%2B6%29%29%2B%28%28x%29%2F%28x-2%29%29=%28%282%29%2F%28x-3%29%29\"
\n" ); document.write( "I need steps and answer! Thanks!
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Algebra.Com's Answer #431452 by ankor@dixie-net.com(22740)\"\" \"About 
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\n" ); document.write( "Factor the 1st denominator
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\n" ); document.write( "we can multiply thru be (x-2)(x-3) and get rid of the denominators, resulting in:
\n" ); document.write( "(x-1) + x(x-3) = 2(x-2)
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\n" ); document.write( "x - 1 + x^2 - 3x = 2x - 4
\n" ); document.write( "Combine like terms on the right
\n" ); document.write( "x^2 + x - 3x - 2x + 4 = 0
\n" ); document.write( "A quadratic equation
\n" ); document.write( "x^2 - 4x + 4 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-2)(x-2) = 0
\n" ); document.write( "x = 2, however this cannot be a solution,
\n" ); document.write( "Substitute 2 for x, the 1st and 2nd denominators would have division by 0
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