document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=699581>Question 699581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this operation: \r<BR>\n" );
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document.write( "1/(4^(1/3) + 2^(1/3) + 1)\r<BR>\n" );
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document.write( "is there a relationship with 2^(1/3) - 1 ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #431429 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=431429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes.<BR>\n" );
document.write( "That is equal to your complicated expression.<BR>\n" );
document.write( "Here is the best explanation I can type from my cell phone:<BR>\n" );
document.write( "If that is a-1, your denominator is<BR>\n" );
document.write( "a squared + a +1<BR>\n" );
document.write( "and their product is<BR>\n" );
document.write( "a cubed - 1 .<BR>\n" );
document.write( "In other words,<BR>\n" );
document.write( "That times your denominator equals<BR>\n" );
document.write( "2 - 1 , which is 1.  </SPAN>\n" );
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