document.write( "Question 699551: 5a-b=12
\n" );
document.write( "7a-3b=20 \r
\n" );
document.write( "\n" );
document.write( "find a and b.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #431428 by Simnepi(216)![]() ![]() You can put this solution on YOUR website! 5a-b=12 call this Equation (1) \n" ); document.write( "7a-3b=20 call this Equation (2) \n" ); document.write( "to solve this we rearrange one of the equations, let's do equation (1). \n" ); document.write( "Rearranging (1) gives \n" ); document.write( "-b=12-5a Let's change the signs of each term (this is the same as multiplying everything by -1) giving \n" ); document.write( "b=5a-12 let's call this equation (3) \n" ); document.write( "Substitute this value into equation (2) giving \n" ); document.write( "7a-3*(5a-12)=20 multiplying out the bracket gives \n" ); document.write( "7a-15a+36=20 \n" ); document.write( "simplifying this gives \n" ); document.write( "-8a=-16 \n" ); document.write( "thus \n" ); document.write( "a=2 \n" ); document.write( "Now we have a value for a we can use this to work out b \n" ); document.write( "substitute a=2 into one of the equations (1), (2) or (3) \n" ); document.write( "(3) seems the simplest one so we'll use that. \n" ); document.write( "b=5*2-12 \n" ); document.write( "therefore \n" ); document.write( "b=-2 \n" ); document.write( " \n" ); document.write( " |