document.write( "Question 699470: A number between 300 and 400 is 40 times the sum of its digits. The tens digit is six more then the units digit. Find the number. \n" ); document.write( "
Algebra.Com's Answer #431412 by MathTherapy(10549)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A number between 300 and 400 is 40 times the sum of its digits. The tens digit is six more then the units digit. Find the number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since number is between 300 and 400, then the hundreds digit MUST be 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the tens, and units digits be T, and U, respectively \n" ); document.write( "Then: 300 + 10T + U = 40(3 + T + U) \n" ); document.write( "300 + 10T + U = 120 + 40T + 40U \n" ); document.write( "10T – 40T + U – 40U = 120 – 300 \n" ); document.write( "- 30T – 39U = - 180 \n" ); document.write( "- 3(10T + 13U) = - 3(60) \n" ); document.write( "10T + 13U = 60 ------ eq (i) \n" ); document.write( "T = U + 6 ------ eq (ii)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10(U + 6) + 13U = 60 --------- Substituting U + 6 for T in eq (i) \n" ); document.write( "10U + 60 + 13U = 60 \n" ); document.write( "23U = 0 \n" ); document.write( "U, or units digit = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T = 0 + 6 ------ Substituting 0 for U in eq (ii) \n" ); document.write( "T, or tens digit = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three-digit number between 300 and 400 = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do the check!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |