document.write( "Question 699361: Use the substitution method to solve th linear system\r
\n" ); document.write( "\n" ); document.write( "5x-4y=50
\n" ); document.write( "10x+y=10\r
\n" ); document.write( "\n" ); document.write( "i keep getting fraction answers.. Please Help~
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Algebra.Com's Answer #431358 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
When trying substitution, look for the variable without a number in front of it.
\n" ); document.write( "Substitution works well when one of the variables' coefficients is \"1\",
\n" ); document.write( "as in the invisible coefficient in front of the \"y\" in \"10x%2By=10\".
\n" ); document.write( "Then, you \"solve\" for that variable in that equation,
\n" ); document.write( "to get an expression for that variable in terms of the other variable:
\n" ); document.write( "\"10x%2By=10\" --> \"y=10-10x\"
\n" ); document.write( "Then you substitute the expression found for the variable in the other equation.
\n" ); document.write( "\"5x-4y=50\" --> \"5x-4%2810-10x%29=50\" --> \"5x-40%2B40x=50\" --> \"45x-40=50\" --> \"45x=50%2B40\" --> \"45x=90\" --> \"x=90%2F45\" --> \"highlight%28x=2%29\"
\n" ); document.write( "The next step is substituting \"2\" for \"x\" in \"y=10-10x\" to get
\n" ); document.write( "\"y=10-10%2A20\" --> \"y=10-20\" --> \"highlight%28y=-10%29\"
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\n" ); document.write( "For \"system%285x-4y=50%2C10x%2By=10%29\" ,
\n" ); document.write( "if you try to use substitution a different way, you end up with fractions.
\n" ); document.write( "It is possible to do it, but I would not try it,
\n" ); document.write( "because I am likely to make some mistake as the calculations get complicated.
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