document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62354>Question 62354</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Right angle triangle that has a line drawn parallel to the base line of the triangle.  <BR>\n" );
document.write( "The top angle of the triangle is A, the right angle is B, and the last angle is C.  There is a line about 2/3 of the way down between A and B, creating D.<BR>\n" );
document.write( "This line segment will be called DE it runs parallel to BC.  \r<BR>\n" );
document.write( "\n" );
document.write( "AD=4, DB=2, BC=8.  I figured out that AC=10 using the pythagorean theorem.  But I can't figure out how to get DE or AE or EC.  I've tried all sorts of equations and can't come up with an answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43134 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Right angle triangle that has a line drawn parallel to the base line of the triangle. <BR>\n" );
document.write( "The top angle of the triangle is A, the right angle is B, and the last angle is C. There is a line about 2/3 of the way down between A and B, creating D.<BR>\n" );
document.write( "This line segment will be called DE it runs parallel to BC. <BR>\n" );
document.write( "AD=4, DB=2, BC=8. I figured out that AC=10 using the pythagorean theorem. But I can't figure out how to get DE or AE or EC. I've tried all sorts of equations and can't come up with an answer.<BR>\n" );
document.write( "YOU ARE CORRECT USING PYTHOGARUS THEOREM <BR>\n" );
document.write( "AC^2=AB^2+BC^2=6^2+8^2=100<BR>\n" );
document.write( "AC=10<BR>\n" );
document.write( "TO FIND DE,AE,EC, WE USE PROPERTIES OF SIMILAR TRIANGLES.IF YOU ARE NOT CONVERSANT WITH THAT THEN USE THE FOLLOWING METHOD<BR>\n" );
document.write( "IN TRIANGLE ABC<BR>\n" );
document.write( "DE||BC.....GIVEN.HENCE<BR>\n" );
document.write( "AD/DB=AE/EC<BR>\n" );
document.write( "AE/EC=4/2=2<BR>\n" );
document.write( "AE=2EC<BR>\n" );
document.write( "AC=10=AE+EC=2EC+EC=3EC<BR>\n" );
document.write( "EC=10/3<BR>\n" );
document.write( "AE=AC-EC=10 - 10/3 = 20/3<BR>\n" );
document.write( "SINCE DE||BC,ANGLE ADE = ANGLE ABC=90....CORRESPONDING ANGLES.<BR>\n" );
document.write( "SO IN RIGHT ANGLED TRIANGLE ADE,<BR>\n" );
document.write( "AD=4,AE=20/3..HENCE<BR>\n" );
document.write( "AD^2+DE^2=AE^2<BR>\n" );
document.write( "16+DE^2=400/9<BR>\n" );
document.write( "DE^2=400/9 -16 = 256/9<BR>\n" );
document.write( "DE= 16/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );