document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=699349>Question 699349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine whether the equation defines y as a function of x.\r<BR>\n" );
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document.write( "x+y=9\r<BR>\n" );
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document.write( "and\r<BR>\n" );
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document.write( "x^2+y^2=1\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "x=y^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #431329 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=431329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine whether the equation defines y as a function of x. <BR>\n" );
document.write( "x+y=9<BR>\n" );
document.write( "y = -x+9<BR>\n" );
document.write( "y is a function of x.<BR>\n" );
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document.write( "x^2+y^2=1<BR>\n" );
document.write( "y = +-sqrt(-x^2+1)<BR>\n" );
document.write( "y is not a function as there are two y-value for some values of \"x\".\r<BR>\n" );
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document.write( "and <BR>\n" );
document.write( "x=y^2<BR>\n" );
document.write( "y = +-sqrt(x)<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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