document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62402>Question 62402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 31.) (a+3i)+(2+bi)=i\r<BR>\n" );
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document.write( "33.) (5-the square root of -4)-(a+bi)=6\r<BR>\n" );
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document.write( "I know how to do the problems that do not have an equal to (ie =i or =6) but I do not understand how to do these. Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43127 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 31.) (a+3i)+(2+bi)=i<BR>\n" );
document.write( "2A+ABi+6i+3B(i)^2=i..........i^2=-1<BR>\n" );
document.write( "(2A-3B)+i(AB+6)=i..REAL PARTS AND IMAGINARY PARTS ON BOTH SIDES OF = MUST BE SAME. HENCE<BR>\n" );
document.write( "2A-3B=0....A=3B/2=1.5B<BR>\n" );
document.write( "AB+6=1<BR>\n" );
document.write( "1.5B*B=-5<BR>\n" );
document.write( "B^2=-5/1.5=-10/3<BR>\n" );
document.write( "B= i*SQRT(10/3)<BR>\n" );
document.write( "A=i*1.5*SQRT(10/3)<BR>\n" );
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document.write( "33.) (5-the square root of -4)-(a+bi)=6 <BR>\n" );
document.write( "USING SAME LOGIC AND METHOD AS ABOVE<BR>\n" );
document.write( "5-4i-A-Bi=6<BR>\n" );
document.write( "(5-A)+i(-4-B)=6<BR>\n" );
document.write( "5-A=6<BR>\n" );
document.write( "A=5-6=-1<BR>\n" );
document.write( "-4-B=0<BR>\n" );
document.write( "B=-4<BR>\n" );
document.write( "I know how to do the problems that do not have an equal to (ie =i or =6) but I do not understand how to do these. Please help<BR>\n" );
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