document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62402>Question 62402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 31.) (a+3i)+(2+bi)=i\r<BR>\n" );
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document.write( "33.) (5-the square root of -4)-(a+bi)=6\r<BR>\n" );
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document.write( "I know how to do the problems that do not have an equal to (ie =i or =6) but I do not understand how to do these. Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43125 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43125\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 31.) (a+3i)+(2+bi)=i <BR>\n" );
document.write( "Combine the Real number terms and the Complex number terms to get:<BR>\n" );
document.write( "(a+2)+(3+b)i=0+1i<BR>\n" );
document.write( "Equate the Real number of the left with the Real number on the right.<BR>\n" );
document.write( "Do the same for the Complex number parts.<BR>\n" );
document.write( "a+2=0 implies a=-2<BR>\n" );
document.write( "3+b=1 implies b=-2<BR>\n" );
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document.write( "33.) (5-the square root of -4)-(a+bi)=6 <BR>\n" );
document.write( "(5-2i)-(a+bi)= 6 + 0i<BR>\n" );
document.write( "(5-a)+(-2-b)i=6+0i<BR>\n" );
document.write( "5-a=6 implies that a=-1<BR>\n" );
document.write( "-2-b=0 implies that b=-2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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