document.write( "Question 699123: \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a number consists of two digits whose sum is 9.if 9 is added to the number ,its digits are reversed .find the number
\n" ); document.write( "

Algebra.Com's Answer #431212 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
10x+y+9=10y+x
\n" ); document.write( "x+y=9 or x=9-y
\n" ); document.write( "10(9-y)+y+9=10y+(9-y)
\n" ); document.write( "90-10y+y+9=10y+9-y
\n" ); document.write( "-10y+y-10y+y=9-90-9
\n" ); document.write( "-18y=-90
\n" ); document.write( "y=-90/-18
\n" ); document.write( "y=5 ans. for the original units digit.
\n" ); document.write( "x=9-5
\n" ); document.write( "x=4 ans. for the tebns digit.
\n" ); document.write( "Proof:
\n" ); document.write( "45+9=54 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );