document.write( "Question 699133: The present age of A and his father is in the ratio of 2:5 respectively.4 years hence the ratio of their ages will become 5:11 respectively.what was father's age 5 years ago? \n" ); document.write( "
Algebra.Com's Answer #431193 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The present age of A and his father is in the ratio of 2:5 respectively. \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "5a = 2f \n" ); document.write( "a = \n" ); document.write( "a = .4f \n" ); document.write( ": \n" ); document.write( "4 years hence the ratio of their ages will become 5:11 respectively. \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "11(a+4) = 5(f+4) \n" ); document.write( "11a + 44 = 5f + 20 \n" ); document.write( "11a = 5f + 20 - 44 \n" ); document.write( "11a = 5f - 24 \n" ); document.write( "replace a with .4f \n" ); document.write( "11(.4f) = 5f - 24 \n" ); document.write( "4.4f = 5f - 24 \n" ); document.write( "24 = 5f - 4.4 \n" ); document.write( "24 = .6f \n" ); document.write( "f = 24/.6 \n" ); document.write( "f = 40 yrs is Dad's present age \n" ); document.write( "then \n" ); document.write( "a = .4(40) \n" ); document.write( "a = 16 is A's present age \n" ); document.write( ": \n" ); document.write( "what was father's age 5 years ago? You can figure that out, I know \n" ); document.write( " |