document.write( "Question 359501: How do you prove exterior angles of a polygon to equal 360? Please don't use the circle diagram, where when all the angles are pulled in to create a circle therefore it equals 360. i want the step by step way to actually prove why the angles to equal 360. \n" ); document.write( "
Algebra.Com's Answer #431172 by Edwin McCravy(20064)\"\" \"About 
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document.write( "There are n exterior angles and n interior angles.\r\n" );
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document.write( "Each exterior angle is supplementary to an interior angle.\r\n" );
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document.write( "At each of the n corners there is a linear pair consisting of\r\n" );
document.write( "an interior angle and an exterior angle.  That's n×180°, as the\r\n" );
document.write( "sum of all interior and exterior angles.\r\n" );
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document.write( "The sum of the n interior angles is (n-2)×180°\r\n" );
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document.write( "Subtract the sum of the interior angles from the sum of the \r\n" );
document.write( "n linear pairs at the corners, which is the sum of all\r\n" );
document.write( "interior and exterior angles, and that will leave the sum of\r\n" );
document.write( "the exterior angles.\r\n" );
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document.write( "n×180° -  (n-2)×180° = [n-(n-2)]×180° = [n-n+2]×180° = 2×180° = 360°\r\n" );
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document.write( "Edwin
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