document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62351>Question 62351</A>: <I><SPAN STYLE=\"word-break: break-all;\"> theres a jar of nickels and dimes that has $6.75. theres 84 more nickels than dimes. how many nickels and how many dimes are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43114 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5N+10D=675<BR>\n" );
document.write( "N=D+84 NOW SUBSTITUTE(D+84) FOR N IN THE FIRST EQUATION THUS<BR>\n" );
document.write( "5(D+84)+10D=675<BR>\n" );
document.write( "15D+420=675<BR>\n" );
document.write( "15D=675-420<BR>\n" );
document.write( "15D=255<BR>\n" );
document.write( "D=255/15<BR>\n" );
document.write( "D=17 NUMBER OF DIMES THEN THE NICKELS ARE 17+84=101<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "5*101+17*10=675<BR>\n" );
document.write( "505+170=675<BR>\n" );
document.write( "675=675 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );