document.write( "Question 698966: How do I graph 2x+y=2? \n" ); document.write( "
Algebra.Com's Answer #431129 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! First solve for y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+y=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+y-2x=2-2x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = -2x + 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Looking at \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have one point \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, because the slope is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "which shows us that the rise is -2 and the run is 1. This means that to go from point to point, we can go down 2 and over 1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So starting at \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and to the right 1 unit to get to the next point \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |