document.write( "Question 62357: Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of the year is $490, how much did he invest at 8%? \n" ); document.write( "
Algebra.Com's Answer #43112 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .08X+.17(5000-X)=490 \n" ); document.write( ".08X+850-.17X=490 \n" ); document.write( "-.09X=-360 \n" ); document.write( "X=-360/-.09 \n" ); document.write( "X=$4000 INVESTED @ 8% & THE REST 5000-4000=$1000 WAS INVESTED @ 17% \n" ); document.write( "PROOF \n" ); document.write( ".08*4000+.17*1000=490 \n" ); document.write( "320+170=490 \n" ); document.write( "490=490 \n" ); document.write( " |