document.write( "Question 698781: How do I solve triangle ABC, given A = 43 degrees, a = 13 and c = 16? Not sure how to figure out side b. The triangle is not a right angled triangle.\r
\n" ); document.write( "\n" ); document.write( "Thanks.
\n" ); document.write( "Matt
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Algebra.Com's Answer #431057 by Simnepi(216)\"\" \"About 
You can put this solution on YOUR website!
You need to use the cosine rule, which is
\n" ); document.write( "\"a%5E2+=+b%5E2+%2B+c%5E2+-+2%2Ab%2Ac%2ACosA\"
\n" ); document.write( "Substitute in the values for the variables to give
\n" ); document.write( "\"13%5E2+=+b%5E2+%2B+16%5E2+-+2%2Ab%2A16%2ACos43\"
\n" ); document.write( "to give
\n" ); document.write( "169 = \"b%5E2\" + 256 - 23.403*b
\n" ); document.write( "rearranging gives
\n" ); document.write( "\"b%5E2\" - 23.403b + 87 = 0
\n" ); document.write( "now if we let b = x we get
\n" ); document.write( "\"x%5E2\" - 23.304x + 87 = 0
\n" ); document.write( "Now we can solve this equation using the formula for quadratic solutions eg
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" so
\n" ); document.write( "\"x+=+%28-23.403+%2B-+sqrt+%28-23.403%5E2+-+4%2A1%2A87%29%29%2F%282%2A1%29\"
\n" ); document.write( "calculating this gives us 2 values for x(b)
\n" ); document.write( "these are x = 18.767 or x = 4.636
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