document.write( "Question 698798: Find the value of c such that the domain of f(x) = sqrt(c-x^2) is [-13,13] \n" ); document.write( "
Algebra.Com's Answer #431048 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+sqrt%28c-x%5E2%29\" ....if the point is at [\"-13\",\"13\"], means \"x=-13\" and \"f%28x%29=13\"; so, we will plug it in formula\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+sqrt%28c-x%5E2%29\" and solve for \"c\"\r
\n" ); document.write( "\n" ); document.write( "\"13+=+sqrt%28c-%28-13%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"13+=+sqrt%28c-169%29\"...both sides raise to power of two\r
\n" ); document.write( "\n" ); document.write( "\"13%5E2+=+%28sqrt%28c-169%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"169+=+c-169\"\r
\n" ); document.write( "\n" ); document.write( "\"169%2B169+=+c\"\r
\n" ); document.write( "\n" ); document.write( "\"338=+c\"\r
\n" ); document.write( "\n" ); document.write( "so, you have a function \"f%28x%29+=+sqrt%28338-x%5E2%29\" that has a solution set \"x=-13\" and \"f%28x%29=13\"\r
\n" ); document.write( "\n" ); document.write( "let's see it on a graph:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-15%2C+15%2C+-15%2C+15%2C+sqrt%28338-x%5E2%29-13%29+\"
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