document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=698793>Question 698793</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x2-20x=0. The problem is 5xto the second power </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #431046 by </B><A HREF=/tutors/aboutme.mpl?userid=Simnepi><B>Simnepi(216)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simnepi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simnepi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=431046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Because the unknown (x) is raised to the power 2 there will be 2 possible values for x.<BR>\n" );
document.write( "First we can factorise the expression by removing a common factor.<BR>\n" );
document.write( "Both terms on the left hand side of the equals sign have an x in them (5x^2 is 5*x*x and 20x is 20*x) so we can remove it, the x, to the outside of a bracket thus<BR>\n" );
document.write( "x(5x-20) = 0<BR>\n" );
document.write( "Because this equals 0(zero) one of the terms in the above expression must equal zero since zero times anything is always zero<BR>\n" );
document.write( "This means that <BR>\n" );
document.write( "x (the term outside the bracket) = 0 (this is one possible value for x)<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "5x-20 (the term inside the bracket) = 0<BR>\n" );
document.write( "we now solve this bit to find out the other value for x<BR>\n" );
document.write( "5x-20 = 0 which means that<BR>\n" );
document.write( "5x = 20<BR>\n" );
document.write( "so x = 4 (your other value for x) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );