document.write( "Question 698704: If the numerator and denominator of a certain fraction are increased by 1, the value of the fraction is 1/2. if the numerator of the original fraction is left unchanged and the denominator is increased by 3, the value of the fraction is 1/4. Find the original fraction. \r
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Algebra.Com's Answer #430987 by sofiyac(983)\"\" \"About 
You can put this solution on YOUR website!
let numerator be x and denominator be y, then our fraction is x/y. Now we follow the problem and create equauations
\n" ); document.write( "\"%28x%2B1%29%2F%28y%2B1%29=1%2F2\"
\n" ); document.write( "\"x%2F%28y%2B3%29=1%2F4\"
\n" ); document.write( "we multiply each equation across and get
\n" ); document.write( "2(x+1)=y+1
\n" ); document.write( "4x=y+3
\n" ); document.write( "********simplify first equaiton
\n" ); document.write( "2x+2=y+1
\n" ); document.write( "4x=y+3
\n" ); document.write( "********subtract 2 from each side on the first equation
\n" ); document.write( "2x=y-1
\n" ); document.write( "4x=y+3
\n" ); document.write( "********multiply first equation by -2
\n" ); document.write( "-4x=-2y+2
\n" ); document.write( "4x=y+3
\n" ); document.write( "**********add the two equations
\n" ); document.write( "0=-y+5 add y to each side
\n" ); document.write( "y=5
\n" ); document.write( "now we plug that into any of the equations since they are all true and solve for x, i'll use the 4x=y+3 equation\r
\n" ); document.write( "\n" ); document.write( "4x=5+3
\n" ); document.write( "4x=8 divide each side by 4
\n" ); document.write( "x=2
\n" ); document.write( "so we said original fraction was x/y so 2/5
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