document.write( "Question 698704: If the numerator and denominator of a certain fraction are increased by 1, the value of the fraction is 1/2. if the numerator of the original fraction is left unchanged and the denominator is increased by 3, the value of the fraction is 1/4. Find the original fraction. \r
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document.write( "THANK YOU if you work this one out! \n" );
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Algebra.Com's Answer #430987 by sofiyac(983)![]() ![]() You can put this solution on YOUR website! let numerator be x and denominator be y, then our fraction is x/y. Now we follow the problem and create equauations \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "we multiply each equation across and get \n" ); document.write( "2(x+1)=y+1 \n" ); document.write( "4x=y+3 \n" ); document.write( "********simplify first equaiton \n" ); document.write( "2x+2=y+1 \n" ); document.write( "4x=y+3 \n" ); document.write( "********subtract 2 from each side on the first equation \n" ); document.write( "2x=y-1 \n" ); document.write( "4x=y+3 \n" ); document.write( "********multiply first equation by -2 \n" ); document.write( "-4x=-2y+2 \n" ); document.write( "4x=y+3 \n" ); document.write( "**********add the two equations \n" ); document.write( "0=-y+5 add y to each side \n" ); document.write( "y=5 \n" ); document.write( "now we plug that into any of the equations since they are all true and solve for x, i'll use the 4x=y+3 equation\r \n" ); document.write( "\n" ); document.write( "4x=5+3 \n" ); document.write( "4x=8 divide each side by 4 \n" ); document.write( "x=2 \n" ); document.write( "so we said original fraction was x/y so 2/5 \n" ); document.write( " |