document.write( "Question 698636: The width of a rectangle is 6 cm less than the length. A second rectangle, with a perimeter of 54 cm, is 3cm wider and 2 cm shorter than the first. Write an equation to help you find the dimensions of both rectangles. \n" ); document.write( "
Algebra.Com's Answer #430978 by sofiyac(983)\"\" \"About 
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width of first rectangle = x
\n" ); document.write( " length of first rectangle = x+6
\n" ); document.write( "width of the second rectangle = x+3
\n" ); document.write( " length of second rectangle = x+4 \r
\n" ); document.write( "\n" ); document.write( "2(x+3)+2(x+4)=54
\n" ); document.write( "2x+6+2x+8=54
\n" ); document.write( "4x=40
\n" ); document.write( "x=10\r
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\n" ); document.write( "\n" ); document.write( "Substituting x:
\n" ); document.write( "width of first rectangle = x = 10 cm
\n" ); document.write( " length of first rectangle = x+6 = 16 cm
\n" ); document.write( "width of the second rectangle = x+3 = 13 cm
\n" ); document.write( " length of second rectangle = x+4 = 14 cm
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