document.write( "Question 698684: Factor out the common factor of: 16x^5-12x^4+20x^3+12x^2
\n" ); document.write( "When I think I have it partly figured out I get confused.
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Algebra.Com's Answer #430953 by Positive_EV(69)\"\" \"About 
You can put this solution on YOUR website!
First, break apart each term into its prime factors:
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\n" ); document.write( "\n" ); document.write( "\"16x%5E5+=+2%2A2%2A2%2A2%2Ax%2Ax%2Ax%2Ax%2Ax\"
\n" ); document.write( "\"12x%5E4+=+2%2A2%2A3%2Ax%2Ax%2Ax%2Ax\"
\n" ); document.write( "\"20x%5E3+=+2%2A2%2A5%2Ax%2Ax%2Ax\"
\n" ); document.write( "\"12x%5E2+=+2%2A2%2A3%2Ax%2Ax\"
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\n" ); document.write( "\n" ); document.write( "In order to factor, a number or variable must appear in every one of the individual terms' prime factorizations. The numbers shared by every term in the polynomial is
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\n" ); document.write( "\n" ); document.write( "\"2%2A2%2Ax%2Ax+=+4%2Ax%5E2\", which is the term that can be factored out of the expression. The expression can be factored as:
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\n" ); document.write( "\n" ); document.write( ", which equals
\n" ); document.write( "\"%284%2Ax%5E2%29%2A%284%2Ax%5E3-3%2Ax%5E2%2B5%2Ax%2B3%29\"
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