document.write( "Question 698675: can you define the variable, write an inequality, and solve the problem. It says: The sum of two consecutive positive even integers is at most 15. What are the possible pairs of integers. \n" ); document.write( "

Algebra.Com's Answer #430940 by sofiyac(983) $\"\"$ $\"About$

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It says: The sum of two consecutive positive even integers is at most 15. What are the possible pairs of integers.
\n" ); document.write( "consecutive positive even integers...so first one would be 2x, we mulitply x by two in order to make sure it's even (divisible by 2). Then the next even integer would be 2x+2. Now add them and make has to be less than or equal to 15.
\n" ); document.write( " $\"2x%2B2x%2B3%3C=15\"$
\n" ); document.write( " $\"4x%2B3%3C=15\"$ subtract 3 from each side
\n" ); document.write( " $\"4x%3C=12\"$ divide each side by 4
\n" ); document.write( " $\"x%3C=3\"$ so if x is less than or equal to 3 than x could be 1 or 2 or 3. In which case our first combination would be 2x and 2x+2 so 2*1 and 2*1+2. Then plug in x=2 and x=3. So the possible pairs of integers are
\n" ); document.write( "1) 2 and 4
\n" ); document.write( "2) 4 and 6
\n" ); document.write( "3) 6 and 8 \n" ); document.write( "

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