document.write( "Question 698269: write the equation of the hyperbola with vertices (6,0) and (-6,0) and an asymptote of y=1/2x \n" ); document.write( "
Algebra.Com's Answer #430893 by lwsshak3(11628)\"\" \"About 
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write the equation of the hyperbola with vertices (6,0) and (-6,0) and an asymptote of y=1/2x
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\n" ); document.write( "This is a hyperbola with horizontal transverse axis.
\n" ); document.write( "Its standard form of equation: (x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center
\n" ); document.write( "..
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "center: (0,0)
\n" ); document.write( "length of horizontal transverse axis=12=2a (-6 to 6)
\n" ); document.write( "a=6
\n" ); document.write( "a^2=36
\n" ); document.write( "For hyperbolas with horizontal transverse axis, slope of asymptotes=b/a
\n" ); document.write( "b/a=1/2
\n" ); document.write( "b=a/2
\n" ); document.write( "b=6/2=3
\n" ); document.write( "b^2=9
\n" ); document.write( "Equation:
\n" ); document.write( "x^2/36-y^2/9=1
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