document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62376>Question 62376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried to set this one up but have been unsuccessful in getting the solution.  Can anyone help me out?\r<BR>\n" );
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document.write( "Find each value of x.\r<BR>\n" );
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document.write( "log1/2 16 =x\r<BR>\n" );
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document.write( "the 1/2 next to the log in like an exponent but below it.  I hope it is clear enough.  Thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43089 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log1/2 16 =x <BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Since 1/2 is the base the corresponding exponential equation is:<BR>\n" );
document.write( "(1/2)^x=16\r<BR>\n" );
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document.write( "1/2^x=16<BR>\n" );
document.write( "Invert both sides to get:<BR>\n" );
document.write( "2^x=1/16<BR>\n" );
document.write( "Rewrite using base 2 to get:<BR>\n" );
document.write( "2^x=2^-4<BR>\n" );
document.write( "x=-4<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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