document.write( "Question 698642: Hi, thanks for your help in advance!
\n" ); document.write( "Ok so the problem is: \"Three years from now, Bob will be three times as old as he was three years ago. How old is Bob now?\"
\n" ); document.write( "I did try to solve this problem on my own, and found that Bob is 6 years old now, but I'm not sure that that is right. I set up my problem like this:
\n" ); document.write( "3+x=3(x-3)
\n" ); document.write( "3+x=3x-9
\n" ); document.write( "12=2x
\n" ); document.write( "6=x\r
\n" ); document.write( "\n" ); document.write( "Is this correct? Thank you for your time and help!
\n" ); document.write( "

Algebra.Com's Answer #430886 by algebrahouse.com(1659)\"\" \"About 
You can put this solution on YOUR website!
x = Bob's age now
\n" ); document.write( "x + 3 = Bob's age in 3 years
\n" ); document.write( "x - 3 = Bob's age 3 years ago\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x + 3 = 3(x - 3) {three years from now (x + 3), Bob will be 3 times his age 3 years ago (x - 3)}
\n" ); document.write( "x + 3 = 3x - 9 {used distributive property}
\n" ); document.write( "12 = 2x {subtracted x and added 9 to each side}
\n" ); document.write( "x = 6 {divided each side by 2}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Bob is 6 now
\n" ); document.write( "
For more help from me, visit: www.algebrahouse.com



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