document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=698553>Question 698553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture has an initial population of 600. After 4 hours the population has grown to 1200. Assuming the culture grows at a rate proportional to the size of the population , find the function representing the population size after t hours and determine the size of the population after 8 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #430881 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=430881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture has an initial population of 600. After 4 hours the population has grown to 1200. Assuming the culture grows at a rate proportional to the size of the population , find the function representing the population size after t hours and determine the size of the population after 8 hours.\r<BR>\n" );
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document.write( "A(t) = Ao*b^t<BR>\n" );
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document.write( "Using t = 4, Ao = 600 ; A(4) = 1200, solve for \"b\":<BR>\n" );
document.write( "1200 = 600*b^4<BR>\n" );
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document.write( "b^4 = 2<BR>\n" );
document.write( "b = 2^(1/4) = 1.1892<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "A(t) = 600*(1.1892)^t<BR>\n" );
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document.write( "A(8) = 600*(1.1892)^8<BR>\n" );
document.write( "A(8) = 2400<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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